fàcil : 2 x + 5x + 6 = 0 , si usamos la forma normal no te sale tenes k usar la formula general : -b +- V (b)2 - 4 (a)(c) 2(a) -(5) +- V (5)2 - 4 (1)(6) 2 (1) -5 +- V 25- 24 = -5 +-V1 = -5 +- 1 2 2 2 x1= (-5 + 1)/ 2= -2 x2= (-5-1)/2= -3 Salñudos !
[tex]x^{2}+5x+6=0\\ utiliza\ la\ siguiente\ fórmula\\ \\ x=\frac{-b+-\sqrt{b^{2}-4ac}}{2a}\\ \\ x=\frac{-5+-\sqrt{5^{2}-4\cdot1\cdot6}}{2\cdot1}=\frac{-5+-\sqrt{25-24}}{2}=\frac{-5+-\sqrt{1}}{2}=\frac{-5+-1}{2}=\\ \\ de\ aqui\ salen\ las\ dos\ soluciones\\ \\ x_{1}=\frac{-5+1}{2}=\frac{-4}{2}=-2\\ \\ x_{2}=\frac{-5-1}{2}=\frac{-6}{2}=-3 [/tex]
